Question:
The first four terms of an AP whose first term is – 2 and the common difference is-2 are
(a) -2,0,2, 4
(b) -2, 4, -8,16
(c) -2,-4,-6,-8
(d) -2, – 4, -8, -16
Solution:
(c) Let the first four terms of an AP are a, a + d, a + 2d and a + 3d.
Given, that first term, a = – 2 and common difference, d = – 2, then we have an AP as follows
-2, – 2 – 2, – 2 + 2(-2), – 2 + 3(-2)
= – 2, – 4, – 6, – 8