The expression $\sim(\sim p \rightarrow q)$ is logically equvalent to :
$\sim \mathrm{p}^{\wedge} \sim \mathrm{q}$
$\mathrm{p}^{\wedge} \mathrm{q}$
$\sim p^{\wedge} \mathrm{q}$
$p^{\wedge} \sim q$
Correct Option: 1
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