Question: The equivalent resistance of the given circuit between the terminals $\mathrm{A}$ and $\mathrm{B}$ is :
$0 \Omega$
$3 \Omega$
$\frac{9}{2} \Omega$
$1 \Omega$
Correct Option: , 4
Solution:
$R_{e q}=\frac{3 \times 3 / 2}{3+3 / 2}=\frac{9 / 2}{9 / 2}=1 \Omega$
