Question: The equation that is incorrect is -
$\left(\Lambda_{\mathrm{m}}^{0}\right)_{\mathrm{NaBr}}-\left(\Lambda_{\mathrm{m}}^{0}\right)_{\mathrm{Nal}}=\left(\Lambda_{\mathrm{m}}^{0}\right)_{\mathrm{KBr}}-\left(\Lambda_{\mathrm{m}}^{0}\right)_{\mathrm{NaBr}}$
$\left(\Lambda_{\mathrm{m}}^{0}\right)_{\mathrm{H}_{2} \mathrm{O}}=\left(\Lambda_{\mathrm{m}}^{0}\right)_{\mathrm{HCl}}+\left(\Lambda_{\mathrm{m}}^{0}\right)_{\mathrm{NaOH}}-\left(\Lambda_{\mathrm{m}}^{0}\right)_{\mathrm{NaCl}}$
$\left(\Lambda_{\mathrm{m}}^{0}\right)_{\mathrm{KCl}}-\left(\Lambda_{\mathrm{m}}^{0}\right)_{\mathrm{NaCl}}=\left(\Lambda_{\mathrm{m}}^{0}\right)_{\mathrm{KBr}}-\left(\Lambda_{\mathrm{m}}^{0}\right)_{\mathrm{NaBr}}$
$\left(\Lambda_{\mathrm{m}}^{0}\right)_{\mathrm{NaBr}}-\left(\Lambda_{\mathrm{m}}^{0}\right)_{\mathrm{NaCl}}=\left(\Lambda_{\mathrm{m}}^{0}\right)_{\mathrm{KBr}}-\left(\Lambda_{\mathrm{m}}^{0}\right)_{\mathrm{KCl}}$
Correct Option: 1
Solution: