Question:
The equation of the tangent at $(2,3)$ on the curve $y^{2}=a x^{3}+b$ is $y=4 x-5$. Find the values of $a$ and $b$.
Solution:
finding the slope of the tangent by differentiating the curve
$2 y \frac{d y}{d x}=3 a x^{2}$
$\frac{d y}{d x}=\frac{3 a x^{2}}{2 y}$
$\mathrm{m}$ (tangent) at $(2,3)=2 \mathrm{a}$
equation of tangent is given by $y-y_{1}=m($ tangent $)\left(x-x_{1}\right)$
now comparing the slope of a tangent with the given equation
$2 a=4$
$a=2$
now $(2,3)$ lies on the curve, these points must satisfy
$3^{2}=2 \times 2^{3}+b$
$b=-7$