Question:
The equation of the line through the point $(0,1,2)$ and perpendicular to the line $\frac{x-1}{2}=\frac{y+1}{3}=\frac{z-1}{-2}$ is :
Correct Option: 1
Solution:
$\frac{x-1}{2}=\frac{y+1}{3}=\frac{z-1}{-2}=\lambda$
Any point on this line $(2 \lambda+1,3 \lambda-1,-2 \lambda+1)$
Direction ratio of given line $(2,3,-2)$
Direction ratio of line to be found $(2 \lambda+1,3 \lambda-2,-2 \lambda-1)$
$\therefore \overrightarrow{\mathrm{d}}_{1} \cdot \overrightarrow{\mathrm{d}}_{2}=0$
$\lambda=2 / 17$
Direction ratio of line $(21,-28,-21) \equiv(3,-4,-3) \equiv(-3,4,3)$