The equation of the hyperbola whose foci are (–2,0) and (2, 0) and eccentricity is 2 is given
by :
$-3 x^{2}+y^{2}=3$
$x^{2}-3 y^{2}=3$
$3 x^{2}-y^{2}=3$
$-x^{2}+3 y^{2}=3$
Correct Option: , 3
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