Question: The equation of the circle passing through the foci of the ellipse $\frac{x^{2}}{16}+\frac{y^{2}}{9}=1$ and having centre at $(0,3)$ is :
$x^{2}+y^{2}-6 y-7=0$
$x^{2}+y^{2}-6 y+7=0$
$x^{2}+y^{2}-6 y-5=0$
$x^{2}+y^{2}-6 y+5=0$
Correct Option: 1
Solution:
