The equation of the circle passing through the points (1, 0) and (0, 1) and having the
smallest radius is -
$x^{2}+y^{2}+x+y-2=0$
$x^{2}+y^{2}-2 x-2 y+1=0$
$x^{2}+y^{2}-x-y=0$
$x^{2}+y^{2}+2 x+2 y-7=0$
Correct Option: , 3
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