The energy dissipated by a resistor is 10 mJ in 1 s when an electric current of 2 mA flows through it.
Question:
The energy dissipated by a resistor is $10 \mathrm{~mJ}$ in $1 \mathrm{~s}$ when an electric current of $2 \mathrm{~mA}$ flows through it. The resistance is $\Omega$ (Round off to the Nearest Integer)
Solution:
Ans. $(2500)$
$Q=i^{2} R T$
$R=\frac{Q}{i^{2} t}=\frac{10 \times 10^{-3}}{4 \times 10^{-6} \times 1}=2500 \Omega$
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