Question:
The domain of the function $f(x)=\sqrt{9-x}+\frac{1}{\sqrt{x^{2}-16}}$ is equal to
Solution:
$f(x)=\sqrt{9-x}+\frac{1}{\sqrt{x^{2}-16}}$
here f(x) is defined for 9 − x ≥ 0
i.e 9 ≥ x
i.e x ≤ 9
and x2 − 16 > 0
i.e x2 > 16
i.e x > 4 or x < −4
∴ f(x) is defined for common region is (−∞, −4) ∪ (4, 9]
∴ Domain of f(x) is (−∞, −4) ∪ (4, 9]