The distance of the point P(- 6, 8)

Question:

The distance of the point P(- 6, 8) from the origin is

(a) 8                         

(b) 2√7                     

(c) 10                        

(d) 6

Solution:

(c) ∴Distance between the points (x1,y2)and (x2, y2)

$d=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}$

Here, $\quad x_{1}=-6, y_{1}=8$ and $x_{2}=0, y_{2}=0$

$\therefore$ Distance between $P(-6,8)$ and origin i.e., $O(0,0)$,

$P O=\sqrt{[0-(-6)]^{2}+(0-8)^{2}}$

$=\sqrt{(6)^{2}+(-8)^{2}}$

 

$=\sqrt{36+64}=\sqrt{100}=10$

 

Leave a comment