The distance of the point $(1,-5,9)$ from the plane $x-y+z=5$ measured along the line $\mathrm{x}=\mathrm{y}=\mathrm{z}$ is :
$\frac{20}{3}$
$3 \sqrt{10}$
$10 \sqrt{3}$
$\frac{10}{\sqrt{3}}$
Correct Option: , 3
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