The distance of the point $(1,0,2)$ from the point of intersection of the line
$\frac{x-2}{3}=\frac{y+1}{4}=\frac{z-2}{12}$ and the plane $x-y+z=16$, is :
$3 \sqrt{21}$
13
$2 \sqrt{14}$
8
Correct Option: , 2
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