Question:
The distance between the points (0, 5) and (- 5, 0) is
(a) 5
(b) 5√2
(c)2√5
(d) 10
Solution:
$d=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}$
Here, $x_{1}=0, y_{1}=5$ and $x_{2}=-5, y_{2}=0$
$\therefore$ Distance between the points $(0,5)$ and $(-5,0)$
$=\sqrt{(-5-0)^{2}+(0-5)^{2}}$
$=\sqrt{25+25}=\sqrt{50}=5 \sqrt{2}$