Question: The dipole moments of $\mathrm{CCl}_{4}, \mathrm{CHCl}_{3}$ and $\mathrm{CH}_{4}$ are in the order:
$\mathrm{CHCl}_{3}<\mathrm{CH}_{4}=\mathrm{CCl}_{4}$
$\mathrm{CCl}_{4}<\mathrm{CH}_{4}<\mathrm{CHCl}_{3}$
$\mathrm{CH}_{4}<\mathrm{CCl}_{4}<\mathrm{CHCl}_{3}$
$\mathrm{CH}_{4}=\mathrm{CCl}_{4}<\mathrm{CHCl}_{3}$
Correct Option: , 4
Solution:
