The difference of squares of two numbers is 180.

Solution:

Let the larger and smaller number be x and y respectively.

According to the given question,

$x^{2}-y^{2}=180$ and $y^{2}=8 x$

$\Rightarrow x^{2}-8 x=180$

$\Rightarrow x^{2}-8 x-180=0$

$\Rightarrow x^{2}-18 x+10 x-180=0$

$\Rightarrow x(x-18)+10(x-18)=0$

$\Rightarrow(x-18)(x+10)=0$

$\Rightarrow x=18,-10$

However, the larger number cannot be negative as 8 times of the larger number will be negative and hence, the square of the smaller number will be negative which is not possible. Therefore, the larger number will be 18 only

$x=18$

$\therefore \quad y^{2}=8 x=8 \times 18=144$

$\Rightarrow y=\pm \sqrt{\mathbf{1 4 4}}=\pm 12$

$\therefore$ Smaller number $=\pm 12$

Therefore, the numbers are 18 and 12 or 18 and $-12$.