Question: The difference in the number of unpaired electrons of a metal ion in its high-spin and low-spin octahedral complexes is two. The metal ion is :
$\mathrm{Fe}^{2+}$
$\mathrm{Co}^{2+}$
$\mathrm{Mn}^{2+}$
$\mathrm{Mn}^{2+}$
Correct Option: 2,
Solution:
$\mathrm{Co}^{2+}$
