The diameters of two circular ends of a bucket are 44 cm and 24 cm,

(b) 32.7 litres
Let R and r be the radii of the top and base of the bucket, respectively, and let h be its height

Then, $R=\frac{44}{2} \mathrm{~cm}=22 \mathrm{~cm}, r=\frac{24}{2} \mathrm{~cm}=12 \mathrm{~cm}, h=35 \mathrm{~cm}$

Capacity of the bucket = Volume of the frustum of the cone

$=\frac{1}{3} \pi h\left[R^{2}+r^{2}+R r\right] \mathrm{cm}^{3}$

$=\frac{1}{3} \times \frac{22}{7} \times 35 \times\left[(22)^{2}+(12)^{2}+(22 \times 12)\right] \mathrm{cm}^{3}$

$=\left(\frac{110}{3} \times 892\right) \mathrm{cm}^{3}$

$=\left(\frac{110 \times 892}{3 \times 1000}\right)$ litres

$=32.7$ litres

Hence, the capacity of the bucket is 32.7 litres.