The de Broglie wavelength of an electron in the $4^{\text {th }}$ Bohr orbit is :
$8 \pi \mathrm{a}_{0}$
$2 \pi \mathrm{a}_{0}$
$4 \pi \mathrm{a}_{0}$
$6 \pi a_{0}$
Correct Option: 1
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