Question.
The cost of 2 kg of apples and 1 kg of grapes on a day was found to be ` 160. After a month, the cost of 4 kg of apples and 2 kg of grapes is ` 300. Represent the situation algebraically and geometrically.
The cost of 2 kg of apples and 1 kg of grapes on a day was found to be ` 160. After a month, the cost of 4 kg of apples and 2 kg of grapes is ` 300. Represent the situation algebraically and geometrically.
Solution:
Let the cost of 1 kg of apple be ` x
and the cost of 1 kg of grapes be ` y
So, $2 x+y=160$
$4 x+2 y=300 x$
and
Let the cost of 1 kg of apple be ` x
and the cost of 1 kg of grapes be ` y
So, $2 x+y=160$
$4 x+2 y=300 x$
![. The cost of 2 kg of apples and](/media/uploads/2021/12/The-cost-of-2-kg-of-apples-and.png)
![The cost of 2 kg of apples and 1 kg](/media/uploads/2021/12/The-cost-of-2-kg-of-apples-and-1-kg.png)
and
![The cost of 2 kg of apples and 1 kg of](/media/uploads/2021/12/The-cost-of-2-kg-of-apples-and-1-kg-of.png)
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