Question: The correct statement about $\mathrm{B}_{2} \mathrm{H}_{6}$ is:
All B-H-B angles are of $120^{\circ}$.
Its fragment, $\mathrm{BH}_{3}$, behaves as a Lewis base.
Terminal B-H bonds have less p-character when compared to bridging bonds.
The two $\mathrm{B}-\mathrm{H}-\mathrm{B}$ bonds are not of same length.
Correct Option: , 3
Solution:
Terminal bond angle is greater than that of bridge bond angle Bond angle
Bond order $\propto$ S-character
