Question: The correct sequence of reagents used in the preparation of 4-bromo-2-nitroethyl benzene from benzene is :
$\mathrm{HNO}_{3} / \mathrm{H}_{2} \mathrm{SO}_{4}, \mathrm{Br}_{2} / \mathrm{AlCl}_{3}, \mathrm{CH}_{3} \mathrm{COCl} / \mathrm{AlCl}_{3}$,$\mathrm{Zn}-\mathrm{Hg} / \mathrm{HCl}$
$\mathrm{Br}_{2} / \mathrm{AlBr}_{3}, \mathrm{CH}_{3} \mathrm{COCl} / \mathrm{AlCl}_{3}, \mathrm{HNO}_{3} / \mathrm{H}_{2} \mathrm{SO}_{4}$,$\mathrm{Zn} / \mathrm{HCl}$
$\mathrm{CH}_{3} \mathrm{COCl} / \mathrm{AlCl}_{3}, \mathrm{Br}_{2} / \mathrm{AlBr}_{3}, \mathrm{HNO}_{3} / \mathrm{H}_{2} \mathrm{SO}_{4}$,$\mathrm{Zn} / \mathrm{HCl}$
$\mathrm{CH}_{3} \mathrm{COCl} / \mathrm{AlCl}_{3}, \mathrm{Zn}-\mathrm{Hg} / \mathrm{HCl}, \mathrm{Br}_{2} / \mathrm{AlBr}_{3}$,$\mathrm{HNO}_{3} / \mathrm{H}_{2} \mathrm{SO}_{4}$
Correct Option: , 4
Solution:
