The correct order of bond

Question:

The correct order of bond dissociation enthalpy of halogens is :

  1. $\mathrm{Cl}_{2}>\mathrm{F}_{2}>\mathrm{Br}_{2}>\mathrm{I}_{2}$

  2. $\mathrm{I}_{2}>\mathrm{Br}_{2}>\mathrm{Cl}_{2}>\mathrm{F}_{2}$

  3. $\mathrm{Cl}_{2}>\mathrm{Br}_{2}>\mathrm{F}_{2}>\mathrm{I}_{2}$

  4. $\mathrm{F}_{2}>\mathrm{Cl}_{2}>\mathrm{Br}_{2}>\mathrm{I}_{2}$


Correct Option: , 3

Solution:

Correct order of bond dissociation enthalpy of halogens is $\mathrm{Cl}_{2}>\mathrm{Br}_{2}>\mathrm{F}_{2}>\mathrm{I}_{2}$.

Due to inter electronic repulsions $\mathrm{F}-\mathrm{F}$ bond becomes weak and easily broken.

Leave a comment