Question:
The coordination number of $\mathrm{Th}$ in $\mathrm{K}_{4}\left[\mathrm{Th}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right]_{4}\left(\mathrm{OH}_{2}\right)_{2}\right]$ is :-
$\left(\mathrm{C}_{2} \mathrm{O}_{4}^{2-}=\right.$ Oxalato $)$
Correct Option: , 2
Solution:
$\mathrm{C}_{2} \mathrm{O}_{4}^{2-}$ (oxalato): bidentate
$\mathrm{H}_{2} \mathrm{O}$ (aqua) : Monodentate