Question: The compound statement $(P \vee Q) \wedge(\sim P) \Rightarrow Q$ is equivalent to:
$P \vee Q$
$P \wedge \sim Q$
$\sim(\mathrm{P} \Rightarrow \mathrm{Q})$
$\sim(\mathrm{P} \Rightarrow \mathrm{Q}) \Leftrightarrow \mathrm{P} \wedge \sim \mathrm{Q}$
Correct Option: 1
Solution:
Using Truth Table
