The Bohr model for the H-atom relies on

The Bohr model for the H-atom relies on the Coulomb’s law of electrostatics. Coulomb’s law has not directly been verified for very short distances of the order of angstroms. Supposing Coulomb’s law between two opposite charge + q1, –q2 is modified to

$|F|=\frac{q_{1} q_{2}}{\left(4 \pi \epsilon_{0}\right)} \frac{1}{r^{2}}, r \geq R_{0}$

$=\frac{q_{1} q_{2}}{\left(4 \pi \epsilon_{0}\right)} \frac{1}{R_{0}^{2}}\left(\frac{R_{0}}{r}\right)^{\epsilon}, r \leq R_{0} \quad$ Calculate in such a case, the ground state energy of an $\mathrm{H}$-atom,

if ε = 0.1, R0 = 1Å.