The base of an isosceles triangle is 16 cm and its area is 48 cm2.

(b) 36 cm

Let $\triangle P Q R$ be an isosceles triangle and $P X \perp Q R$.

Now,

Area of triangle $=48 \mathrm{~cm}^{2}$

$\Rightarrow \frac{1}{2} \times Q R \times P X=48$

$\Rightarrow h=\frac{96}{16}=6 \mathrm{~cm}$

Also,

$Q X=\frac{1}{2} \times 24=12 \mathrm{~cm}$ and $P X=12 \mathrm{~cm}$

$P Q=\sqrt{Q X^{2}+P X^{2}}$

$a=\sqrt{8^{2}+6^{2}}=\sqrt{64+36}=\sqrt{100}=10 \mathrm{~cm}$

$\therefore$ Perimeter $=(10+10+16) \mathrm{cm}=36 \mathrm{~cm}$