Question:
The Balmer series in the hydrogen spectrum corresponds to the transition from n1 = 2 to n2 = 3,4,………. This series lies in the visible region. Calculate the wavenumber of the line associated with the transition in Balmer series when the electron moves to n = 4 orbit. (RH= 109677 cm-1)
Solution:
According to Bohr’s model for the hydrogen atom
ν = RH(1/n12-1/ n22)cm-1
here, n1 = 2 and n2 = 4 and H = Rydberg’s constant = 109677
Hence, wave number -v= 109677 ( ¼-1/16)
= 20564.44cm-1