Question: The area of the triangle with vertices $\mathrm{A}(\mathrm{z}), \mathrm{B}(\mathrm{iz})$ and $\mathrm{C}(\mathrm{z}+\mathrm{iz})$ is :
1
$\frac{1}{2}|z|^{2}$
$\frac{1}{2}$
$\frac{1}{2}|z+i z|^{2}$
Correct Option: , 2
Solution:
$\mathrm{A}=\frac{1}{2}|\mathrm{z}||\mathrm{iz}|$
$=\frac{|\mathrm{z}|^{2}}{2}$
