The area of the base of a right circular cylinder is 616 cm

Let the area of the base of a right circular cylinder be $S \mathrm{~cm}^{2}$.

Given :

$S=616 \mathrm{~cm}^{2}$

Height, $h=25 \mathrm{~cm}$

Let the radius of a right circular cylinder be $r \mathrm{~cm}$.

$S=\pi r^{2}$

$616=\frac{22}{7} \times \mathrm{r}^{2}$

$\mathbf{r}^{2}=\frac{616 \times 7}{22}$

$\mathrm{r}^{2}=196$

r = 14 cm

Volume of the cylinder, $\mathrm{V}=\pi r^{2} h$

$=\pi \times(14)^{2} \times 25$

$=15400 \mathrm{~cm}^{3}$