The area of an equilateral triangle is

Area of equilateral triangle $=49 \sqrt{3}$

$\Rightarrow \frac{\sqrt{3}}{4} \times(\text { Side })^{2}=49 \sqrt{3}$

$\Rightarrow(\text { Side })^{2}=7^{2} \times 2^{2}$

$\Rightarrow$ Side $=14 \mathrm{~cm}$

Radius of the circle = Half of the side of the triangle = 7 cm
Area of triangle not included in the circle = Area of triangle − Area of 3 sectors having central angle 60∘

$=49 \sqrt{3}-3 \times \frac{60^{\circ}}{360^{\circ}} \times \frac{22}{7} \times 7 \times 7$

$=84.77-77$

$=7.77 \mathrm{~cm}^{2}$

Hence, the required area is 7.77 cm2