Question:
The area of a trapezium is 960 cm2. If the parallel sides are 34 cm and 46 cm, find the distance between them.
Solution:
Given;
Area of the trapezium $=960 \mathrm{~cm}^{2}$
And the length of the parallel sides are $34 \mathrm{~cm}$ and $46 \mathrm{~cm}$.
Area of trapezium $=\frac{1}{2} \times($ Sum of the parallel sides $) \times($ Perpendicular distance between the parallel sides $)$
$\Rightarrow 960=\frac{1}{2} \times(34+46) \times($ Height $)$
$\Rightarrow 960=40 \times($ Height $)$
$\Rightarrow$ Height $=\frac{960}{40}=24 \mathrm{~cm}$