Question:
The area of a room is $65 \frac{1}{4} \mathrm{~m}^{2}$. If its breadth is $5 \frac{7}{16}$ metres, what is its length?
Solution:
Area of a room $=$ Length $\times$ Breadth Thus, we have:
$65 \frac{1}{4}=$ Length $\times 5 \frac{7}{16}$
Length $=65 \frac{1}{4} \div 5 \frac{7}{16}$
$=\left(65+\frac{1}{4}\right) \div\left(5+\frac{7}{16}\right)$
$=\frac{261}{4} \div \frac{87}{16}$
$=\frac{261}{4} \times \frac{16}{87}$
$=\frac{261 \times 16}{4 \times 87}$
$=\frac{4176}{348}$
$=12 \mathrm{~m}$
Hence, the length of the room is 12 metres.