The area of a rhombus is equal to the area of a triangle whose base and the corresponding altitude are 24.8 cm and 16.5 cm respectively.

Given:

Area of the rhombus = Area of the triangle with base $24.8 \mathrm{~cm}$ and altitude $16.5 \mathrm{~cm}$

Area of the triangle $=\frac{1}{2} \times$ base $\times$ altitude $=\frac{1}{2} \times 24.8 \times 16.5=204.6 \mathrm{~cm}^{2}$

$\therefore$ Area of the rhombus $=204.6 \mathrm{~cm}^{2}$

Also, length of one of the diagonals of the rhombus $=22 \mathrm{~cm}$

We know : Area of rhombus $=\frac{1}{2}\left(d_{1} \times d_{2}\right)$

$204.6=\frac{1}{2}\left(22 \times d_{2}\right)$

$22 \times d_{2}=409.2$

$d_{2}=\frac{409.2}{22}=18.6 \mathrm{~cm}$

Hence, the length of the other diagonal of the rhombus is $18.6 \mathrm{~cm}$.