The area of a rhombus is 240 cm

Given:

Area of the rhombus $=240 \mathrm{~cm}$

Length of one of its diagonals $=16 \mathrm{~cm}$

We know that if the diagonals of a rhombus are $\mathrm{d}_{1}$ and $\mathrm{d}_{2}$, then the area of the rhombus is given by :

Area $=\frac{1}{2}\left(\mathrm{~d}_{1} \times \mathrm{d}_{2}\right)$

Putting the given values:

$240=\frac{1}{2}\left(16 \times \mathrm{d}_{2}\right)$

$240 \times 2=16 \times \mathrm{d}_{2}$

This can be written as follows:

$16 \times \mathrm{d}_{2}=480$

$\mathrm{~d}_{2}=\frac{480}{16}$

$\mathrm{~d}_{2}=30 \mathrm{~cm}$

Thus, the length of the other diagonal of the rhombus is $30 \mathrm{~cm}$.