Question:
The area (in sq. units) of the region, given by the
set $\left\{(x, y) \in \mathbf{R} \times \mathbf{R} \mid x \geq 0,2 x^{2} \leq y \leq 4-2 x\right\}$ is :
Correct Option: , 4
Solution:
Required area $=\int_{0}^{1}\left(4-2 x-2 x^{2}\right) d x=4 x-x^{2}-\left.\frac{2 x^{3}}{3}\right|_{0} ^{1}$
$=4-1-\frac{2}{3}=\frac{7}{3}$
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