Question: The area (in sq. units) of the region
$\begin{aligned} A=&\{(x, y) \in R \times R \mid 0 \leq x \leq 3,0 \leq y \leq 4\\ &\left.y \leq x^{2}+3 x\right\} \text { is : } \end{aligned}$
$\frac{53}{6}$
$\frac{59}{6}$
8
$\frac{26}{3}$
Correct Option: , 2
Solution:
