The additive inverse of

Question:

The additive inverse of $\frac{-7}{19}$ is

(a) $-7 / 19$

(b) $7 / 19$

(c) $19 / 7$

(d) $-19 / 7$

Solution:

Additive inverse of $(-7 / 19)$ is (b) $(7 / 19)$

The additive inverse of the rational number $-a / b$ is $a / b$ and vice-versa.

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