Question:
Swati took a loan of Rs 16000 against her insurance policy at the rate of $12 \frac{1}{2} \%$ per annum. Calculate the total compound interest payable by Swati after 3 years.
Solution:
Given:
$\mathrm{P}=$ Rs 16,000
$\mathrm{R}=12.5 \%$ p. a.
$\mathrm{n}=3$ years
We know that:
$\mathrm{A}=\mathrm{P}\left(1+\frac{\mathrm{R}}{100}\right)^{\mathrm{n}}$
$=16,000\left(1+\frac{12.5}{100}\right)^{3}$
$=16,000(1.125)^{3}$
$=\operatorname{Rs} 22,781.25$
Now,
$\mathrm{CI}=\mathrm{A}-\mathrm{P}$
$=\mathrm{Rs} 22,781.25-\mathrm{Rs} 16,000$
$=\mathrm{Rs} 6,781.25$