Subba Rao started work in 1995 at an annual salary of Rs. 5000 and received an increment of Rs. 200 each year.

Solution:

It can be observed that the incomes that Subba Rao obtained in various years are in A.P. as every

year, his salary is increased by Rs. 200.

Therefore, the salaries of each year after 1995 are

5000, 5200, 5400, .....

Here, a = 5000

d = 200

Let after $\mathrm{n}^{\text {th }}$ year, his salary be Rs 7000 .

Therefore, $a=a+(n-1) d$

$7000=5000+(n-1) 200$

200(n – 1) = 2000

(n – 1) = 10

n = 11

Therefore, in 11th year, his salary will be Rs 7000.