Question:
Statement I : The only circle having radius $\sqrt{10}$ and a diameter along line $2 x+y=5$ is $x^{2}+y^{2}-6 x+2 y=0$.
Statement II : $2 \mathrm{x}+\mathrm{y}=5$ is a normal to the circle $\mathrm{x}^{2}+\mathrm{y}^{2}-6 \mathrm{x}+2 \mathrm{y}=0$.
Correct Option: 1
Solution:
Normal passes through centre of circle but there can be more then one circle.
Click here to get exam-ready with eSaral
For making your preparation journey smoother of JEE, NEET and Class 8 to 10, grab our app now.