Question:
Statement-1 : The variance of first $n$ even natural numbers is $\frac{n^{2}-1}{4}$
Statement-2 : The sum of first n natural numbers is $\frac{n(n+1)}{2}$ and the sum of squares of first $n$ natural numbers is $\frac{\mathrm{n}(\mathrm{n}+1)(2 \mathrm{n}+1)}{6}$.
Correct Option: , 2
Solution:
