State in each case whether A ⊂ B or A ⊄ B.
$A=\left\{x: x \in Z, x^{2}=1\right\}, B=\left\{x: x \in N, x^{2}=1\right\}$
A ⊄ B
Explanation: we have, A = { -1,1} and B={1}
Since, -1∈A and -1∉B thus A ⊄ B .
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