If $g(x)=\int_{0}^{x} \cos 4 t d t$, then $g(x+\pi)$ equals :
$\mathrm{g}(\mathrm{x}) \cdot \mathrm{g}(\pi)$
$\frac{g(x)}{g(\pi)}$
$g(x)+g(\pi)$
$g(x)-g(\pi)$
Correct Option: 3, 4,
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