Question: Let $f(x)= \begin{cases}(x-1)^{\frac{1}{2-x}}, & x>1, x \neq 2 \\ k & , x=2\end{cases}$
The value of $k$ for which $f$ is continuous at $x=2$ is :
$\mathrm{e}^{-1}$
$\mathrm{e}$
$\mathrm{e}^{-2}$
1
Correct Option: 1
Solution:
Solution Not Requird
