Question:
The internal energy (U), pressure $(P)$ and volume $(\mathrm{V})$ of an ideal gas are related as $\mathrm{U}=$ $3 \mathrm{PV}+4$. The gas is :-
Correct Option: , 2
Solution:
$\mathrm{U}=3 \mathrm{PV}+4$
$\frac{\mathrm{nf}}{2} \mathrm{RT}=3 \mathrm{PV}+4$
$\frac{f}{2} P V=3 P V+4$
$f=6+\frac{8}{P V}$
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