Question:
A uniform cylinder of mass $M$ and radius $R$ is to be pulled over a step of height a $(a 
Correct Option: , 4
Solution:
$(\tau)_{\mathrm{P}}=0$
F.R. $-\mathrm{mgx}=0$
$x=\sqrt{R^{2}-(R-a)^{2}}$
$F=m g \frac{X}{R}$
$\mathrm{F}=\mathrm{mg} \sqrt{1-\left(\frac{\mathrm{R}-\mathrm{a}}{\mathrm{R}}\right)^{2}}$
$=$ minimum value of force to pull