Question: $10.30 \mathrm{mg}$ of $\mathrm{O}_{2}$ is dissolved into a liter of sea water of density $1.03 \mathrm{~g} / \mathrm{mL}$. The concentration of $\mathrm{O}_{2}$ in ppm is
Solution:
$\mathrm{ppm}=\frac{10.3 \times 10^{-3}}{1030} \times 10^{6}=10$
