Question:
Mark $(\sqrt{)}$ against the correct answer in each of the following:
$\int x \sin x \cos x d x=?$
A. $-\frac{1}{4} x \sin 2 x+\frac{1}{8} \cos 2 x+C$
B. $\frac{1}{4} x \cos 2 x-\frac{1}{8} \sin 2 x+C$
C. $\frac{1}{2} \mathrm{x} \sin 2 \mathrm{x}+\frac{1}{4} \cos 2 \mathrm{x}+\mathrm{C}$
D. $-\frac{1}{4} x \cos 2 x+\frac{1}{8} \sin 2 x+C$
Solution:
